What are the solutions to the equation x^2+2ax+a^2=0 ?

The solutions to the equation x^2+2ax+a^2=0 are x=-a

Find the zeros of x^2+2ax+a^2=0

The zeros of x^2+2ax+a^2=0 are x=-a

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x^{2} + 2 a x + a^{2} = 0

x = - a

Solution steps

x^{2} + 2 a x + a^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 a \pm ( 2 a ) ^{2} - 4 \cdot 1 \cdot a ^{2}}{2 \cdot 1}

(2 a)^{2} - 4 \cdot 1 \cdot a^{2} = 0

x_{1, 2} = \frac{- 2 a \pm 0}{2 \cdot 1}

x = \frac{- 2 a}{2 \cdot 1}

Simplify

\frac{- 2 a}{2 \cdot 1} : - a

x = - a

The solution to the quadratic equation is:

x = - a

- x^{2} + 6 x - 8

(9 z + \frac{1}{2})^{2} + 61 = 39

- 40 m^{2} + 10 m - 1 = 0

m^{2} - 11 m + 30 = 0

x^{2} - 5 x - 24 = 0

What are the solutions to the equation x^2+2ax+a^2=0 ?
The solutions to the equation x^2+2ax+a^2=0 are x=-a
Find the zeros of x^2+2ax+a^2=0
The zeros of x^2+2ax+a^2=0 are x=-a