What are the solutions to the equation (x+1)^2=3 ?

The solutions to the equation (x+1)^2=3 are x=sqrt(3)-1,x=-sqrt(3)-1

Find the zeros of (x+1)^2=3

The zeros of (x+1)^2=3 are x=sqrt(3)-1,x=-sqrt(3)-1

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(x + 1)^{2} = 3

x = 3 - 1, x = - 3 - 1

Solution steps

(x + 1)^{2} = 3

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = 3 : x = 3 - 1

Solve

x + 1 = - 3 : x = - 3 - 1

The solutions to the quadratic equation are:

x = 3 - 1, x = - 3 - 1

3 x^{2} - 5 = 13

6 x^{2} - 2 x + 3 = 0

3 x^{2} + 3 x - 7 = 0

x^{2} - 5 = 44

12 - 6 x^{2} = 0

What are the solutions to the equation (x+1)^2=3 ?
The solutions to the equation (x+1)^2=3 are x=sqrt(3)-1,x=-sqrt(3)-1
Find the zeros of (x+1)^2=3
The zeros of (x+1)^2=3 are x=sqrt(3)-1,x=-sqrt(3)-1