What are the solutions to the equation -3x^2-2x+1=0 ?

The solutions to the equation -3x^2-2x+1=0 are x=-1,x= 1/3

Find the zeros of -3x^2-2x+1=0

The zeros of -3x^2-2x+1=0 are x=-1,x= 1/3

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- 3 x^{2} - 2 x + 1 = 0

x = - 1, x = \frac{1}{3}

Solution steps

- 3 x^{2} - 2 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 3 ) \cdot 1}{2 ( - 3 )}

(- 2)^{2} - 4 (- 3) \cdot 1 = 4

x_{1, 2} = \frac{- ( - 2 ) \pm 4}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 4}{2 ( - 3 )}, x_{2} = \frac{- ( - 2 ) - 4}{2 ( - 3 )}

x = \frac{- ( - 2 ) + 4}{2 ( - 3 )} : - 1

x = \frac{- ( - 2 ) - 4}{2 ( - 3 )} : \frac{1}{3}

The solutions to the quadratic equation are:

x = - 1, x = \frac{1}{3}

x^{2} + 64 = - 15 x

2 x^{2} - 162 = 0

6 + 4 x^{2} = 0

x^{2} - 10 x = 75

x^{2} + 14 x - 1 = 0

What are the solutions to the equation -3x^2-2x+1=0 ?
The solutions to the equation -3x^2-2x+1=0 are x=-1,x= 1/3
Find the zeros of -3x^2-2x+1=0
The zeros of -3x^2-2x+1=0 are x=-1,x= 1/3