What are the solutions to the equation x^2+64=-15x ?

The solutions to the equation x^2+64=-15x are x=-15/2+i(sqrt(31))/2 ,x=-15/2-i(sqrt(31))/2

Find the zeros of x^2+64=-15x

The zeros of x^2+64=-15x are x=-15/2+i(sqrt(31))/2 ,x=-15/2-i(sqrt(31))/2

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x^{2} + 64 = - 15 x

x = - \frac{15}{2} + i \frac{31}{2}, x = - \frac{15}{2} - i \frac{31}{2}

Solution steps

x^{2} + 64 = - 15 x

Move

15 x

to the left side

x^{2} + 64 + 15 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 15 x + 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 1 \cdot 64}{2 \cdot 1}

Simplify

1 5^{2} - 4 \cdot 1 \cdot 64 : 31 i

x_{1, 2} = \frac{- 15 \pm 31 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 15 + 31 i}{2 \cdot 1}, x_{2} = \frac{- 15 - 31 i}{2 \cdot 1}

x = \frac{- 15 + 31 i}{2 \cdot 1} : - \frac{15}{2} + i \frac{31}{2}

x = \frac{- 15 - 31 i}{2 \cdot 1} : - \frac{15}{2} - i \frac{31}{2}

The solutions to the quadratic equation are:

x = - \frac{15}{2} + i \frac{31}{2}, x = - \frac{15}{2} - i \frac{31}{2}

2 x^{2} - 162 = 0

6 + 4 x^{2} = 0

x^{2} - 10 x = 75

x^{2} + 14 x - 1 = 0

2 (x + 1)^{2} + 3 = 21

What are the solutions to the equation x^2+64=-15x ?
The solutions to the equation x^2+64=-15x are x=-15/2+i(sqrt(31))/2 ,x=-15/2-i(sqrt(31))/2
Find the zeros of x^2+64=-15x
The zeros of x^2+64=-15x are x=-15/2+i(sqrt(31))/2 ,x=-15/2-i(sqrt(31))/2