What are the solutions to the equation 3(x+2)^2+4=13 ?

The solutions to the equation 3(x+2)^2+4=13 are x=sqrt(3)-2,x=-sqrt(3)-2

Find the zeros of 3(x+2)^2+4=13

The zeros of 3(x+2)^2+4=13 are x=sqrt(3)-2,x=-sqrt(3)-2

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3 (x + 2)^{2} + 4 = 13

x = 3 - 2, x = - 3 - 2

Solution steps

3 (x + 2)^{2} + 4 = 13

Move

4

to the right side

3 (x + 2)^{2} = 9

Divide both sides by

3

(x + 2)^{2} = 3

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = 3 : x = 3 - 2

Solve

x + 2 = - 3 : x = - 3 - 2

The solutions to the quadratic equation are:

x = 3 - 2, x = - 3 - 2

x, 9 x^{2} + 6 y^{2} + 4 x y - y + 2 = 0

y, z = y x^{6} - 3 x + 8 x^{2} y^{2} - y^{2}

2 x^{2} - 4 x - 10 = 0

2 x^{2} - 2 = - 3 x

- 5 z^{2} - 10 z + 1 = - 6 z^{2}

What are the solutions to the equation 3(x+2)^2+4=13 ?
The solutions to the equation 3(x+2)^2+4=13 are x=sqrt(3)-2,x=-sqrt(3)-2
Find the zeros of 3(x+2)^2+4=13
The zeros of 3(x+2)^2+4=13 are x=sqrt(3)-2,x=-sqrt(3)-2