What are the solutions to the equation x^2+x-14=0 ?

The solutions to the equation x^2+x-14=0 are x=(-1+sqrt(57))/2 ,x=(-1-sqrt(57))/2

Find the zeros of x^2+x-14=0

The zeros of x^2+x-14=0 are x=(-1+sqrt(57))/2 ,x=(-1-sqrt(57))/2

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x^{2} + x - 14 = 0

x = \frac{- 1 + 57}{2}, x = \frac{- 1 - 57}{2}

Decimal Notation

x = 3.27491 \dots, x = - 4.27491 \dots

Solution steps

x^{2} + x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 14) = 57

x_{1, 2} = \frac{- 1 \pm 57}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 57}{2 \cdot 1}, x_{2} = \frac{- 1 - 57}{2 \cdot 1}

x = \frac{- 1 + 57}{2 \cdot 1} : \frac{- 1 + 57}{2}

x = \frac{- 1 - 57}{2 \cdot 1} : \frac{- 1 - 57}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 57}{2}, x = \frac{- 1 - 57}{2}

x^{2} + x - 16 = 0

3 (2 x + 4)^{2} - 48 = 30

x^{2} - 13 x - 36 = 0

x^{2} + 10 = 85

y, y^{2} = x^{3}

What are the solutions to the equation x^2+x-14=0 ?
The solutions to the equation x^2+x-14=0 are x=(-1+sqrt(57))/2 ,x=(-1-sqrt(57))/2
Find the zeros of x^2+x-14=0
The zeros of x^2+x-14=0 are x=(-1+sqrt(57))/2 ,x=(-1-sqrt(57))/2