What are the solutions to the equation 3(2x+4)^2-48=30 ?

The solutions to the equation 3(2x+4)^2-48=30 are x=(sqrt(26)-4)/2 ,x=(-sqrt(26)-4)/2

Find the zeros of 3(2x+4)^2-48=30

The zeros of 3(2x+4)^2-48=30 are x=(sqrt(26)-4)/2 ,x=(-sqrt(26)-4)/2

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3 (2 x + 4)^{2} - 48 = 30

x = \frac{26 - 4}{2}, x = \frac{- 26 - 4}{2}

Solution steps

3 (2 x + 4)^{2} - 48 = 30

Move

48

to the right side

3 (2 x + 4)^{2} = 78

Divide both sides by

3

(2 x + 4)^{2} = 26

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x + 4 = 26 : x = \frac{26 - 4}{2}

Solve

2 x + 4 = - 26 : x = \frac{- 26 - 4}{2}

The solutions to the quadratic equation are:

x = \frac{26 - 4}{2}, x = \frac{- 26 - 4}{2}

x^{2} - 13 x - 36 = 0

x^{2} + 10 = 85

y, y^{2} = x^{3}

4 x^{2} + 19 x + 19 = 0

4 x^{2} + 27 = - 20 x

What are the solutions to the equation 3(2x+4)^2-48=30 ?
The solutions to the equation 3(2x+4)^2-48=30 are x=(sqrt(26)-4)/2 ,x=(-sqrt(26)-4)/2
Find the zeros of 3(2x+4)^2-48=30
The zeros of 3(2x+4)^2-48=30 are x=(sqrt(26)-4)/2 ,x=(-sqrt(26)-4)/2