What are the solutions to the equation 2(5x+7)^2-13=33 ?

The solutions to the equation 2(5x+7)^2-13=33 are x=(sqrt(23)-7)/5 ,x=(-sqrt(23)-7)/5

Find the zeros of 2(5x+7)^2-13=33

The zeros of 2(5x+7)^2-13=33 are x=(sqrt(23)-7)/5 ,x=(-sqrt(23)-7)/5

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2 (5 x + 7)^{2} - 13 = 33

x = \frac{23 - 7}{5}, x = \frac{- 23 - 7}{5}

Decimal Notation

x = - 0.44083 \dots, x = - 2.35916 \dots

Solution steps

2 (5 x + 7)^{2} - 13 = 33

Move

13

to the right side

2 (5 x + 7)^{2} = 46

Divide both sides by

2

(5 x + 7)^{2} = 23

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 x + 7 = 23 : x = \frac{23 - 7}{5}

Solve

5 x + 7 = - 23 : x = \frac{- 23 - 7}{5}

The solutions to the quadratic equation are:

x = \frac{23 - 7}{5}, x = \frac{- 23 - 7}{5}

z^{2} - 4 z + 8 = 0

(n + 2) x^{2} - 6 n x + 9 = 0

x^{2} + 14 x + 38 = 0

x^{2} - (m + 7) x + 25 = 0

15 x^{2} - 31 x + 10 = 0

What are the solutions to the equation 2(5x+7)^2-13=33 ?
The solutions to the equation 2(5x+7)^2-13=33 are x=(sqrt(23)-7)/5 ,x=(-sqrt(23)-7)/5
Find the zeros of 2(5x+7)^2-13=33
The zeros of 2(5x+7)^2-13=33 are x=(sqrt(23)-7)/5 ,x=(-sqrt(23)-7)/5