What are the solutions to the equation (6a+2)(8a+7)=0 ?

The solutions to the equation (6a+2)(8a+7)=0 are a=-1/3 ,a=-7/8

Find the zeros of (6a+2)(8a+7)=0

The zeros of (6a+2)(8a+7)=0 are a=-1/3 ,a=-7/8

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(6 a + 2) (8 a + 7) = 0

a = - \frac{1}{3}, a = - \frac{7}{8}

Solution steps

(6 a + 2) (8 a + 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

6 a + 2 = 0 or 8 a + 7 = 0

Solve

6 a + 2 = 0 : a = - \frac{1}{3}

Solve

8 a + 7 = 0 : a = - \frac{7}{8}

The solutions to the quadratic equation are:

a = - \frac{1}{3}, a = - \frac{7}{8}

x^{2} - 9 x = 0

2 (5 x + 7)^{2} - 13 = 33

z^{2} - 4 z + 8 = 0

(n + 2) x^{2} - 6 n x + 9 = 0

x^{2} + 14 x + 38 = 0

What are the solutions to the equation (6a+2)(8a+7)=0 ?
The solutions to the equation (6a+2)(8a+7)=0 are a=-1/3 ,a=-7/8
Find the zeros of (6a+2)(8a+7)=0
The zeros of (6a+2)(8a+7)=0 are a=-1/3 ,a=-7/8