What are the solutions to the equation a=x^2-18x+80 ?

The solutions to the equation a=x^2-18x+80 are x=9+sqrt(a+1),x=9-sqrt(a+1)

Find the zeros of a=x^2-18x+80

The zeros of a=x^2-18x+80 are x=9+sqrt(a+1),x=9-sqrt(a+1)

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a = x^{2} - 18 x + 80

x = 9 + a + 1, x = 9 - a + 1

Solution steps

a = x^{2} - 18 x + 80

Switch sides

x^{2} - 18 x + 80 = a

Move

a

to the left side

x^{2} - 18 x + 80 - a = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot ( 80 - a )}{2 \cdot 1}

Simplify

(- 18)^{2} - 4 \cdot 1 \cdot (80 - a) : 2 a + 1

x_{1, 2} = \frac{- ( - 18 ) \pm 2 a + 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 2 a + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 18 ) - 2 a + 1}{2 \cdot 1}

x = \frac{- ( - 18 ) + 2 a + 1}{2 \cdot 1} : 9 + a + 1

x = \frac{- ( - 18 ) - 2 a + 1}{2 \cdot 1} : 9 - a + 1

The solutions to the quadratic equation are:

x = 9 + a + 1, x = 9 - a + 1

x^{2} + 8 x + 16 = 16

x, y = x^{2} - 2 x - 3

u^{2} - 4 u + 4 = 0

- 0.6 x^{2} + 14 x + 15 = - 0.4 x + 99

x^{2} + 19 x + 88 = 0

What are the solutions to the equation a=x^2-18x+80 ?
The solutions to the equation a=x^2-18x+80 are x=9+sqrt(a+1),x=9-sqrt(a+1)
Find the zeros of a=x^2-18x+80
The zeros of a=x^2-18x+80 are x=9+sqrt(a+1),x=9-sqrt(a+1)