What are the solutions to the equation 5x^2+4=x ?

The solutions to the equation 5x^2+4=x are x= 1/10+i(sqrt(79))/(10),x= 1/10-i(sqrt(79))/(10)

Find the zeros of 5x^2+4=x

The zeros of 5x^2+4=x are x= 1/10+i(sqrt(79))/(10),x= 1/10-i(sqrt(79))/(10)

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5 x^{2} + 4 = x

x = \frac{1}{10} + i \frac{79}{10}, x = \frac{1}{10} - i \frac{79}{10}

Solution steps

5 x^{2} + 4 = x

Move

x

to the left side

5 x^{2} + 4 - x = 0

Write in the standard form

a x^{2} + b x + c = 0

5 x^{2} - x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 5 \cdot 4}{2 \cdot 5}

Simplify

(- 1)^{2} - 4 \cdot 5 \cdot 4 : 79 i

x_{1, 2} = \frac{- ( - 1 ) \pm 79 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 79 i}{2 \cdot 5}, x_{2} = \frac{- ( - 1 ) - 79 i}{2 \cdot 5}

x = \frac{- ( - 1 ) + 79 i}{2 \cdot 5} : \frac{1}{10} + i \frac{79}{10}

x = \frac{- ( - 1 ) - 79 i}{2 \cdot 5} : \frac{1}{10} - i \frac{79}{10}

The solutions to the quadratic equation are:

x = \frac{1}{10} + i \frac{79}{10}, x = \frac{1}{10} - i \frac{79}{10}

x, 4 x^{2} - 9 y^{2} = 0

y^{2} - 6 y - 16 = 0

x^{2} + 5 x - 25 = 0

x^{2} + 2 x - 255 = 0

9 x^{2} + 54 x + 85 = 0

What are the solutions to the equation 5x^2+4=x ?
The solutions to the equation 5x^2+4=x are x= 1/10+i(sqrt(79))/(10),x= 1/10-i(sqrt(79))/(10)
Find the zeros of 5x^2+4=x
The zeros of 5x^2+4=x are x= 1/10+i(sqrt(79))/(10),x= 1/10-i(sqrt(79))/(10)