What are the solutions to the equation y^2-6y-16=0 ?

The solutions to the equation y^2-6y-16=0 are y=8,y=-2

Find the zeros of y^2-6y-16=0

The zeros of y^2-6y-16=0 are y=8,y=-2

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y^{2} - 6 y - 16 = 0

y = 8, y = - 2

Solution steps

y^{2} - 6 y - 16 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 16 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 16) = 10

y_{1, 2} = \frac{- ( - 6 ) \pm 10}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 6 ) + 10}{2 \cdot 1}, y_{2} = \frac{- ( - 6 ) - 10}{2 \cdot 1}

y = \frac{- ( - 6 ) + 10}{2 \cdot 1} : 8

y = \frac{- ( - 6 ) - 10}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

y = 8, y = - 2

x^{2} + 5 x - 25 = 0

x^{2} + 2 x - 255 = 0

9 x^{2} + 54 x + 85 = 0

5 x^{2} - 0.8 x = 0

- 2 x^{2} + 1 = - 6

What are the solutions to the equation y^2-6y-16=0 ?
The solutions to the equation y^2-6y-16=0 are y=8,y=-2
Find the zeros of y^2-6y-16=0
The zeros of y^2-6y-16=0 are y=8,y=-2