What are the solutions to the equation x^2-18x+10=0 ?

The solutions to the equation x^2-18x+10=0 are x=9+sqrt(71),x=9-sqrt(71)

Find the zeros of x^2-18x+10=0

The zeros of x^2-18x+10=0 are x=9+sqrt(71),x=9-sqrt(71)

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x^{2} - 18 x + 10 = 0

x = 9 + 71, x = 9 - 71

Decimal Notation

x = 17.42614 \dots, x = 0.57385 \dots

Solution steps

x^{2} - 18 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

(- 18)^{2} - 4 \cdot 1 \cdot 10 = 271

x_{1, 2} = \frac{- ( - 18 ) \pm 2 71}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 2 71}{2 \cdot 1}, x_{2} = \frac{- ( - 18 ) - 2 71}{2 \cdot 1}

x = \frac{- ( - 18 ) + 2 71}{2 \cdot 1} : 9 + 71

x = \frac{- ( - 18 ) - 2 71}{2 \cdot 1} : 9 - 71

The solutions to the quadratic equation are:

x = 9 + 71, x = 9 - 71

x^{2} - 4 x + 24 = 0

x^{2} - 18 x + 401 = 0

(6 x - 4) (3 x + 5) = (4 x - 9) (3 x + 5)

x^{2} = \frac{4}{9}

x^{2} = 10 x - 74

What are the solutions to the equation x^2-18x+10=0 ?
The solutions to the equation x^2-18x+10=0 are x=9+sqrt(71),x=9-sqrt(71)
Find the zeros of x^2-18x+10=0
The zeros of x^2-18x+10=0 are x=9+sqrt(71),x=9-sqrt(71)