What are the solutions to the equation -x^2-6x+5=0 ?

The solutions to the equation -x^2-6x+5=0 are x=-3-sqrt(14),x=sqrt(14)-3

Find the zeros of -x^2-6x+5=0

The zeros of -x^2-6x+5=0 are x=-3-sqrt(14),x=sqrt(14)-3

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- x^{2} - 6 x + 5 = 0

x = - 3 - 14, x = 14 - 3

Solution steps

- x^{2} - 6 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( - 1 ) \cdot 5}{2 ( - 1 )}

(- 6)^{2} - 4 (- 1) \cdot 5 = 214

x_{1, 2} = \frac{- ( - 6 ) \pm 2 14}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 14}{2 ( - 1 )}, x_{2} = \frac{- ( - 6 ) - 2 14}{2 ( - 1 )}

x = \frac{- ( - 6 ) + 2 14}{2 ( - 1 )} : - 3 - 14

x = \frac{- ( - 6 ) - 2 14}{2 ( - 1 )} : 14 - 3

The solutions to the quadratic equation are:

x = - 3 - 14, x = 14 - 3

n^{2} - 7 n - 2 = 0

(5 x + 5)^{2} + 3 = 39

12 x^{2} - 204 x + 594 = 0

x, z = 3 x^{2} y + 4 x y^{2}

x^{2} + 7 x + 30 = 0

What are the solutions to the equation -x^2-6x+5=0 ?
The solutions to the equation -x^2-6x+5=0 are x=-3-sqrt(14),x=sqrt(14)-3
Find the zeros of -x^2-6x+5=0
The zeros of -x^2-6x+5=0 are x=-3-sqrt(14),x=sqrt(14)-3