What are the solutions to the equation solvefor x,f=(x-h)^2+k ?

The solutions to the equation solvefor x,f=(x-h)^2+k are x=sqrt(f-k)+h,x=-sqrt(f-k)+h

Find the zeros of solvefor x,f=(x-h)^2+k

The zeros of solvefor x,f=(x-h)^2+k are x=sqrt(f-k)+h,x=-sqrt(f-k)+h

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solve for

x, f = (x - h)^{2} + k

x = f - k + h, x = - f - k + h

Solution steps

f = (x - h)^{2} + k

Switch sides

(x - h)^{2} + k = f

Move

k

to the right side

(x - h)^{2} = f - k

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - h = f - k : x = f - k + h

Solve

x - h = - f - k : x = - f - k + h

The solutions to the quadratic equation are:

x = f - k + h, x = - f - k + h

- 4 x^{2} + 5 x - 9 = 0

5 n^{2} - 18 n + 12 = 0

x^{2} - 10 x + 25 = 144

x, - 11 x^{2} + 132 x + 17 y^{2} - 136 y - 124 = 0

(2 x - 7)^{2} = (x - 4)^{2} + (2 x + 3) (2 x - 5)

What are the solutions to the equation solvefor x,f=(x-h)^2+k ?
The solutions to the equation solvefor x,f=(x-h)^2+k are x=sqrt(f-k)+h,x=-sqrt(f-k)+h
Find the zeros of solvefor x,f=(x-h)^2+k
The zeros of solvefor x,f=(x-h)^2+k are x=sqrt(f-k)+h,x=-sqrt(f-k)+h