What are the solutions to the equation -12x^2+24x=0 ?

The solutions to the equation -12x^2+24x=0 are x=0,x=2

Find the zeros of -12x^2+24x=0

The zeros of -12x^2+24x=0 are x=0,x=2

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- 12 x^{2} + 24 x = 0

x = 0, x = 2

Solution steps

- 12 x^{2} + 24 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 ( - 12 ) \cdot 0}{2 ( - 12 )}

2 4^{2} - 4 (- 12) \cdot 0 = 24

x_{1, 2} = \frac{- 24 \pm 24}{2 ( - 12 )}

Separate the solutions

x_{1} = \frac{- 24 + 24}{2 ( - 12 )}, x_{2} = \frac{- 24 - 24}{2 ( - 12 )}

x = \frac{- 24 + 24}{2 ( - 12 )} : 0

x = \frac{- 24 - 24}{2 ( - 12 )} : 2

The solutions to the quadratic equation are:

x = 0, x = 2

x^{2} - 8 x + 5

4 x^{2} - 3 x - 22 = 0

m^{2} - 4 m - 5 = 0

6 x^{2} - 12 x + 24 = 0

9 (3 + 4 x)^{2} = 25

What are the solutions to the equation -12x^2+24x=0 ?
The solutions to the equation -12x^2+24x=0 are x=0,x=2
Find the zeros of -12x^2+24x=0
The zeros of -12x^2+24x=0 are x=0,x=2