What are the solutions to the equation 6x^2-12x+24=0 ?

The solutions to the equation 6x^2-12x+24=0 are x=1+sqrt(3)i,x=1-sqrt(3)i

Find the zeros of 6x^2-12x+24=0

The zeros of 6x^2-12x+24=0 are x=1+sqrt(3)i,x=1-sqrt(3)i

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6 x^{2} - 12 x + 24 = 0

x = 1 + 3 i, x = 1 - 3 i

Solution steps

6 x^{2} - 12 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 6 \cdot 24}{2 \cdot 6}

Simplify

(- 12)^{2} - 4 \cdot 6 \cdot 24 : 123 i

x_{1, 2} = \frac{- ( - 12 ) \pm 12 3 i}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 12 3 i}{2 \cdot 6}, x_{2} = \frac{- ( - 12 ) - 12 3 i}{2 \cdot 6}

x = \frac{- ( - 12 ) + 12 3 i}{2 \cdot 6} : 1 + 3 i

x = \frac{- ( - 12 ) - 12 3 i}{2 \cdot 6} : 1 - 3 i

The solutions to the quadratic equation are:

x = 1 + 3 i, x = 1 - 3 i

9 (3 + 4 x)^{2} = 25

x^{2} - 30 x + 81 = 0

(x + 7)^{2} = (2 x - 1)^{2}

x^{2} - \frac{5}{3} x

x^{2} = 12 (x - 5)

What are the solutions to the equation 6x^2-12x+24=0 ?
The solutions to the equation 6x^2-12x+24=0 are x=1+sqrt(3)i,x=1-sqrt(3)i
Find the zeros of 6x^2-12x+24=0
The zeros of 6x^2-12x+24=0 are x=1+sqrt(3)i,x=1-sqrt(3)i