What are the solutions to the equation a^2-10a+52=0 ?

The solutions to the equation a^2-10a+52=0 are a=5+3sqrt(3)i,a=5-3sqrt(3)i

Find the zeros of a^2-10a+52=0

The zeros of a^2-10a+52=0 are a=5+3sqrt(3)i,a=5-3sqrt(3)i

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a^{2} - 10 a + 52 = 0

a = 5 + 33 i, a = 5 - 33 i

Solution steps

a^{2} - 10 a + 52 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 52}{2 \cdot 1}

Simplify

(- 10)^{2} - 4 \cdot 1 \cdot 52 : 63 i

a_{1, 2} = \frac{- ( - 10 ) \pm 6 3 i}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 10 ) + 6 3 i}{2 \cdot 1}, a_{2} = \frac{- ( - 10 ) - 6 3 i}{2 \cdot 1}

a = \frac{- ( - 10 ) + 6 3 i}{2 \cdot 1} : 5 + 33 i

a = \frac{- ( - 10 ) - 6 3 i}{2 \cdot 1} : 5 - 33 i

The solutions to the quadratic equation are:

a = 5 + 33 i, a = 5 - 33 i

m^{2} - m - 12 = 0

5 x^{2} - 8 x + 6 = 0

10 x^{2} - 7 x + 1 = 0

2 (4 x - 3)^{2} - 13 = 29

49 x^{2} - 100 = 0

What are the solutions to the equation a^2-10a+52=0 ?
The solutions to the equation a^2-10a+52=0 are a=5+3sqrt(3)i,a=5-3sqrt(3)i
Find the zeros of a^2-10a+52=0
The zeros of a^2-10a+52=0 are a=5+3sqrt(3)i,a=5-3sqrt(3)i