What are the solutions to the equation 2(4x-3)^2-13=29 ?

The solutions to the equation 2(4x-3)^2-13=29 are x=(sqrt(21)+3)/4 ,x=(-sqrt(21)+3)/4

Find the zeros of 2(4x-3)^2-13=29

The zeros of 2(4x-3)^2-13=29 are x=(sqrt(21)+3)/4 ,x=(-sqrt(21)+3)/4

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2 (4 x - 3)^{2} - 13 = 29

x = \frac{21 + 3}{4}, x = \frac{- 21 + 3}{4}

Decimal Notation

x = 1.89564 \dots, x = - 0.39564 \dots

Solution steps

2 (4 x - 3)^{2} - 13 = 29

Move

13

to the right side

2 (4 x - 3)^{2} = 42

Divide both sides by

2

(4 x - 3)^{2} = 21

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x - 3 = 21 : x = \frac{21 + 3}{4}

Solve

4 x - 3 = - 21 : x = \frac{- 21 + 3}{4}

The solutions to the quadratic equation are:

x = \frac{21 + 3}{4}, x = \frac{- 21 + 3}{4}

49 x^{2} - 100 = 0

x^{2} - 8 x + c = 0

(x + 1) (x - 5) = 16

a^{2} - 8 a + 16 = 0

x^{2} - 34 = 16 x

What are the solutions to the equation 2(4x-3)^2-13=29 ?
The solutions to the equation 2(4x-3)^2-13=29 are x=(sqrt(21)+3)/4 ,x=(-sqrt(21)+3)/4
Find the zeros of 2(4x-3)^2-13=29
The zeros of 2(4x-3)^2-13=29 are x=(sqrt(21)+3)/4 ,x=(-sqrt(21)+3)/4