What are the solutions to the equation m^2-m-12=0 ?

The solutions to the equation m^2-m-12=0 are m=4,m=-3

Find the zeros of m^2-m-12=0

The zeros of m^2-m-12=0 are m=4,m=-3

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m^{2} - m - 12 = 0

m = 4, m = - 3

Solution steps

m^{2} - m - 12 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 12) = 7

m_{1, 2} = \frac{- ( - 1 ) \pm 7}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 1 ) + 7}{2 \cdot 1}, m_{2} = \frac{- ( - 1 ) - 7}{2 \cdot 1}

m = \frac{- ( - 1 ) + 7}{2 \cdot 1} : 4

m = \frac{- ( - 1 ) - 7}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

m = 4, m = - 3

5 x^{2} - 8 x + 6 = 0

10 x^{2} - 7 x + 1 = 0

2 (4 x - 3)^{2} - 13 = 29

49 x^{2} - 100 = 0

x^{2} - 8 x + c = 0

What are the solutions to the equation m^2-m-12=0 ?
The solutions to the equation m^2-m-12=0 are m=4,m=-3
Find the zeros of m^2-m-12=0
The zeros of m^2-m-12=0 are m=4,m=-3