What are the solutions to the equation x^2-8x+c=0 ?

The solutions to the equation x^2-8x+c=0 are x=4+sqrt(-c+16),x=4-sqrt(-c+16)

Find the zeros of x^2-8x+c=0

The zeros of x^2-8x+c=0 are x=4+sqrt(-c+16),x=4-sqrt(-c+16)

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x^{2} - 8 x + c = 0

x = 4 + - c + 16, x = 4 - - c + 16

Solution steps

x^{2} - 8 x + c = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot c}{2 \cdot 1}

Simplify

(- 8)^{2} - 4 \cdot 1 \cdot c : 2 16 - c

x_{1, 2} = \frac{- ( - 8 ) \pm 2 16 - c}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 16 - c}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2 16 - c}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2 16 - c}{2 \cdot 1} : 4 + - c + 16

x = \frac{- ( - 8 ) - 2 16 - c}{2 \cdot 1} : 4 - - c + 16

The solutions to the quadratic equation are:

x = 4 + - c + 16, x = 4 - - c + 16

(x + 1) (x - 5) = 16

a^{2} - 8 a + 16 = 0

x^{2} - 34 = 16 x

9 x^{2} - 24 = 1

- 2 (x - 4)^{2} = - 5

What are the solutions to the equation x^2-8x+c=0 ?
The solutions to the equation x^2-8x+c=0 are x=4+sqrt(-c+16),x=4-sqrt(-c+16)
Find the zeros of x^2-8x+c=0
The zeros of x^2-8x+c=0 are x=4+sqrt(-c+16),x=4-sqrt(-c+16)