What are the solutions to the equation a^2-8a+16=0 ?

The solutions to the equation a^2-8a+16=0 are a=4

Find the zeros of a^2-8a+16=0

The zeros of a^2-8a+16=0 are a=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

a^{2} - 8 a + 16 = 0

a = 4

Solution steps

a^{2} - 8 a + 16 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 16 = 0

a_{1, 2} = \frac{- ( - 8 ) \pm 0}{2 \cdot 1}

a = \frac{- ( - 8 )}{2 \cdot 1}

\frac{- ( - 8 )}{2 \cdot 1} = 4

a = 4

The solution to the quadratic equation is:

a = 4

x^{2} - 34 = 16 x

9 x^{2} - 24 = 1

- 2 (x - 4)^{2} = - 5

6 x^{2} - 10 x - 4 = 0

4 x^{2} - 30 x + 56 = 0

What are the solutions to the equation a^2-8a+16=0 ?
The solutions to the equation a^2-8a+16=0 are a=4
Find the zeros of a^2-8a+16=0
The zeros of a^2-8a+16=0 are a=4