What are the solutions to the equation x^2+14x=-32 ?

The solutions to the equation x^2+14x=-32 are x=-7+sqrt(17),x=-7-sqrt(17)

Find the zeros of x^2+14x=-32

The zeros of x^2+14x=-32 are x=-7+sqrt(17),x=-7-sqrt(17)

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x^{2} + 14 x = - 32

x = - 7 + 17, x = - 7 - 17

Solution steps

x^{2} + 14 x = - 32

Move

32

to the left side

x^{2} + 14 x + 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 32}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot 32 = 217

x_{1, 2} = \frac{- 14 \pm 2 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 2 17}{2 \cdot 1}, x_{2} = \frac{- 14 - 2 17}{2 \cdot 1}

x = \frac{- 14 + 2 17}{2 \cdot 1} : - 7 + 17

x = \frac{- 14 - 2 17}{2 \cdot 1} : - 7 - 17

The solutions to the quadratic equation are:

x = - 7 + 17, x = - 7 - 17

a, a^{2} - b^{2} = 0

2 m^{2} - 3 = 0

(x - 2) (x + 3) = x + 19

x, x^{2} + 3 x y + y^{2} = 5

x (x + 3) = 40

What are the solutions to the equation x^2+14x=-32 ?
The solutions to the equation x^2+14x=-32 are x=-7+sqrt(17),x=-7-sqrt(17)
Find the zeros of x^2+14x=-32
The zeros of x^2+14x=-32 are x=-7+sqrt(17),x=-7-sqrt(17)