What are the solutions to the equation 2m^2-3=0 ?

The solutions to the equation 2m^2-3=0 are m=sqrt(3/2),m=-sqrt(3/2)

Find the zeros of 2m^2-3=0

The zeros of 2m^2-3=0 are m=sqrt(3/2),m=-sqrt(3/2)

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2 m^{2} - 3 = 0

m = \frac{3}{2}, m = - \frac{3}{2}

Decimal Notation

m = 1.22474 \dots, m = - 1.22474 \dots

Solution steps

2 m^{2} - 3 = 0

Move

3

to the right side

2 m^{2} = 3

Divide both sides by

2

m^{2} = \frac{3}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

m = \frac{3}{2}, m = - \frac{3}{2}

(x - 2) (x + 3) = x + 19

x, x^{2} + 3 x y + y^{2} = 5

x (x + 3) = 40

12 x^{2} + 24 x - 6 = 0

12 x^{2} - 13 x - 35 = 0

What are the solutions to the equation 2m^2-3=0 ?
The solutions to the equation 2m^2-3=0 are m=sqrt(3/2),m=-sqrt(3/2)
Find the zeros of 2m^2-3=0
The zeros of 2m^2-3=0 are m=sqrt(3/2),m=-sqrt(3/2)