What are the solutions to the equation (x-2)(x+3)=x+19 ?

The solutions to the equation (x-2)(x+3)=x+19 are x=5,x=-5

Find the zeros of (x-2)(x+3)=x+19

The zeros of (x-2)(x+3)=x+19 are x=5,x=-5

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(x - 2) (x + 3) = x + 19

x = 5, x = - 5

Solution steps

(x - 2) (x + 3) = x + 19

Expand

(x - 2) (x + 3) : x^{2} + x - 6

x^{2} + x - 6 = x + 19

Move

6

to the right side

x^{2} + x = x + 25

Move

x

to the left side

x^{2} = 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 25, x = - 25

25 = 5

- 25 = - 5

x = 5, x = - 5

x, x^{2} + 3 x y + y^{2} = 5

x (x + 3) = 40

12 x^{2} + 24 x - 6 = 0

12 x^{2} - 13 x - 35 = 0

4 x^{2} - x + 6 = 0

What are the solutions to the equation (x-2)(x+3)=x+19 ?
The solutions to the equation (x-2)(x+3)=x+19 are x=5,x=-5
Find the zeros of (x-2)(x+3)=x+19
The zeros of (x-2)(x+3)=x+19 are x=5,x=-5