What are the solutions to the equation 12x^2-13x-35=0 ?

The solutions to the equation 12x^2-13x-35=0 are x= 7/3 ,x=-5/4

Find the zeros of 12x^2-13x-35=0

The zeros of 12x^2-13x-35=0 are x= 7/3 ,x=-5/4

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12 x^{2} - 13 x - 35 = 0

x = \frac{7}{3}, x = - \frac{5}{4}

Decimal Notation

x = 2.33333 \dots, x = - 1.25

Solution steps

12 x^{2} - 13 x - 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 12 ( - 35 )}{2 \cdot 12}

(- 13)^{2} - 4 \cdot 12 (- 35) = 43

x_{1, 2} = \frac{- ( - 13 ) \pm 43}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 43}{2 \cdot 12}, x_{2} = \frac{- ( - 13 ) - 43}{2 \cdot 12}

x = \frac{- ( - 13 ) + 43}{2 \cdot 12} : \frac{7}{3}

x = \frac{- ( - 13 ) - 43}{2 \cdot 12} : - \frac{5}{4}

The solutions to the quadratic equation are:

x = \frac{7}{3}, x = - \frac{5}{4}

4 x^{2} - x + 6 = 0

- 12 x^{2} + 5 x + 2 = 0

- 8 x^{2} + 3 x - 7 = 0

2 x^{2} - 6 = 4 x

- 12 x + 7 = 5 - 2 x^{2}

What are the solutions to the equation 12x^2-13x-35=0 ?
The solutions to the equation 12x^2-13x-35=0 are x= 7/3 ,x=-5/4
Find the zeros of 12x^2-13x-35=0
The zeros of 12x^2-13x-35=0 are x= 7/3 ,x=-5/4