What are the solutions to the equation 12x^2-6x-6=0 ?

The solutions to the equation 12x^2-6x-6=0 are x=1,x=-1/2

Find the zeros of 12x^2-6x-6=0

The zeros of 12x^2-6x-6=0 are x=1,x=-1/2

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12 x^{2} - 6 x - 6 = 0

x = 1, x = - \frac{1}{2}

Solution steps

12 x^{2} - 6 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 12 ( - 6 )}{2 \cdot 12}

(- 6)^{2} - 4 \cdot 12 (- 6) = 18

x_{1, 2} = \frac{- ( - 6 ) \pm 18}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 18}{2 \cdot 12}, x_{2} = \frac{- ( - 6 ) - 18}{2 \cdot 12}

x = \frac{- ( - 6 ) + 18}{2 \cdot 12} : 1

x = \frac{- ( - 6 ) - 18}{2 \cdot 12} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = 1, x = - \frac{1}{2}

x^{2} - 30 x = 0

x^{2} + \frac{2}{5} x + 9

x^{2} + 22 x + 28 = 12 x

2 x^{2} - 5 x - 3 = 2 x - 4 x^{2}

2 (2 x + 1)^{2} = (x + 3)^{2} - 10

What are the solutions to the equation 12x^2-6x-6=0 ?
The solutions to the equation 12x^2-6x-6=0 are x=1,x=-1/2
Find the zeros of 12x^2-6x-6=0
The zeros of 12x^2-6x-6=0 are x=1,x=-1/2