What are the solutions to the equation x^2+22x+28=12x ?

The solutions to the equation x^2+22x+28=12x are x=-5+sqrt(3)i,x=-5-sqrt(3)i

Find the zeros of x^2+22x+28=12x

The zeros of x^2+22x+28=12x are x=-5+sqrt(3)i,x=-5-sqrt(3)i

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x^{2} + 22 x + 28 = 12 x

x = - 5 + 3 i, x = - 5 - 3 i

Solution steps

x^{2} + 22 x + 28 = 12 x

Move

12 x

to the left side

x^{2} + 10 x + 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 28}{2 \cdot 1}

Simplify

1 0^{2} - 4 \cdot 1 \cdot 28 : 23 i

x_{1, 2} = \frac{- 10 \pm 2 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 2 3 i}{2 \cdot 1}, x_{2} = \frac{- 10 - 2 3 i}{2 \cdot 1}

x = \frac{- 10 + 2 3 i}{2 \cdot 1} : - 5 + 3 i

x = \frac{- 10 - 2 3 i}{2 \cdot 1} : - 5 - 3 i

The solutions to the quadratic equation are:

x = - 5 + 3 i, x = - 5 - 3 i

2 x^{2} - 5 x - 3 = 2 x - 4 x^{2}

2 (2 x + 1)^{2} = (x + 3)^{2} - 10

x^{2} - 2 x = 3

7 x^{2} - 18 = 45

9 x^{2} - 6 x + 7 = 0

What are the solutions to the equation x^2+22x+28=12x ?
The solutions to the equation x^2+22x+28=12x are x=-5+sqrt(3)i,x=-5-sqrt(3)i
Find the zeros of x^2+22x+28=12x
The zeros of x^2+22x+28=12x are x=-5+sqrt(3)i,x=-5-sqrt(3)i