What are the solutions to the equation 4x^2-8x+12=0 ?

The solutions to the equation 4x^2-8x+12=0 are x=1+sqrt(2)i,x=1-sqrt(2)i

Find the zeros of 4x^2-8x+12=0

The zeros of 4x^2-8x+12=0 are x=1+sqrt(2)i,x=1-sqrt(2)i

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4 x^{2} - 8 x + 12 = 0

x = 1 + 2 i, x = 1 - 2 i

Solution steps

4 x^{2} - 8 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 4 \cdot 12}{2 \cdot 4}

Simplify

(- 8)^{2} - 4 \cdot 4 \cdot 12 : 82 i

x_{1, 2} = \frac{- ( - 8 ) \pm 8 2 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 8 2 i}{2 \cdot 4}, x_{2} = \frac{- ( - 8 ) - 8 2 i}{2 \cdot 4}

x = \frac{- ( - 8 ) + 8 2 i}{2 \cdot 4} : 1 + 2 i

x = \frac{- ( - 8 ) - 8 2 i}{2 \cdot 4} : 1 - 2 i

The solutions to the quadratic equation are:

x = 1 + 2 i, x = 1 - 2 i

2 x^{2} - 9 = 55

1 + \frac{2 b}{3} + \frac{b ^{2}}{9} = 0

2 x^{2} + 16 x + 34 = 0

- 12 x^{2} - 54 x = 0

- 3 x^{2} + 48 = 0

What are the solutions to the equation 4x^2-8x+12=0 ?
The solutions to the equation 4x^2-8x+12=0 are x=1+sqrt(2)i,x=1-sqrt(2)i
Find the zeros of 4x^2-8x+12=0
The zeros of 4x^2-8x+12=0 are x=1+sqrt(2)i,x=1-sqrt(2)i