What are the solutions to the equation 1+(2b)/3+(b^2)/9 =0 ?

The solutions to the equation 1+(2b)/3+(b^2)/9 =0 are b=-3

Find the zeros of 1+(2b)/3+(b^2)/9 =0

The zeros of 1+(2b)/3+(b^2)/9 =0 are b=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1 + \frac{2 b}{3} + \frac{b ^{2}}{9} = 0

b = - 3

Solution steps

1 + \frac{2 b}{3} + \frac{b ^{2}}{9} = 0

Find Least Common Multiplier of

3, 9 : 9

Multiply by LCM=

9

1 \cdot 9 + \frac{2 b}{3} \cdot 9 + \frac{b ^{2}}{9} \cdot 9 = 0 \cdot 9

Simplify

b^{2} + 6 b + 9 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 9 = 0

b_{1, 2} = \frac{- 6 \pm 0}{2 \cdot 1}

b = \frac{- 6}{2 \cdot 1}

\frac{- 6}{2 \cdot 1} = - 3

b = - 3

The solution to the quadratic equation is:

b = - 3

2 x^{2} + 16 x + 34 = 0

- 12 x^{2} - 54 x = 0

- 3 x^{2} + 48 = 0

3 x^{2} + 6 x - 2 = - 2

12 x^{2} - 200 x + 600 = 0

What are the solutions to the equation 1+(2b)/3+(b^2)/9 =0 ?
The solutions to the equation 1+(2b)/3+(b^2)/9 =0 are b=-3
Find the zeros of 1+(2b)/3+(b^2)/9 =0
The zeros of 1+(2b)/3+(b^2)/9 =0 are b=-3