What are the solutions to the equation -3x^2+48=0 ?

The solutions to the equation -3x^2+48=0 are x=4,x=-4

Find the zeros of -3x^2+48=0

The zeros of -3x^2+48=0 are x=4,x=-4

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- 3 x^{2} + 48 = 0

x = 4, x = - 4

Solution steps

- 3 x^{2} + 48 = 0

Move

48

to the right side

- 3 x^{2} = - 48

Divide both sides by

- 3

x^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 16, x = - 16

16 = 4

- 16 = - 4

x = 4, x = - 4

3 x^{2} + 6 x - 2 = - 2

12 x^{2} - 200 x + 600 = 0

x^{2} + 6 x - 3 = 0

x^{2} + 7 x + 12 = 0

9 x^{2} - 6 x - 3 = 0

What are the solutions to the equation -3x^2+48=0 ?
The solutions to the equation -3x^2+48=0 are x=4,x=-4
Find the zeros of -3x^2+48=0
The zeros of -3x^2+48=0 are x=4,x=-4