What are the solutions to the equation completesquare x^2+6x-3=0 ?

The solutions to the equation completesquare x^2+6x-3=0 are x=2sqrt(3)-3,x=-2sqrt(3)-3

Find the zeros of completesquare x^2+6x-3=0

The zeros of completesquare x^2+6x-3=0 are x=2sqrt(3)-3,x=-2sqrt(3)-3

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x^{2} + 6 x - 3 = 0

x = 23 - 3, x = - 23 - 3

Decimal Notation

x = 0.46410 \dots, x = - 6.46410 \dots

Solution steps

x^{2} + 6 x - 3 = 0

Move

3

to the right side

x^{2} + 6 x = 3

Rewrite in the form

(x + a)^{2} = b

(x + 3)^{2} = 12

For

the solutions are

f (x) = a, - a

Solve

x + 3 = 12 : x = 23 - 3

Solve

x + 3 = - 12 : x = - 23 - 3

The solutions to the quadratic equation are:

x = 23 - 3, x = - 23 - 3

x^{2} + 7 x + 12 = 0

9 x^{2} - 6 x - 3 = 0

(x - 1)^{2} = - 49

m^{2} + 4 m - 9 = 0

2 x^{2} = 5 x + 2

What are the solutions to the equation completesquare x^2+6x-3=0 ?
The solutions to the equation completesquare x^2+6x-3=0 are x=2sqrt(3)-3,x=-2sqrt(3)-3
Find the zeros of completesquare x^2+6x-3=0
The zeros of completesquare x^2+6x-3=0 are x=2sqrt(3)-3,x=-2sqrt(3)-3