What are the solutions to the equation 4x^2+2x-1=-10(x+1) ?

The solutions to the equation 4x^2+2x-1=-10(x+1) are x=-3/2

Find the zeros of 4x^2+2x-1=-10(x+1)

The zeros of 4x^2+2x-1=-10(x+1) are x=-3/2

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4 x^{2} + 2 x - 1 = - 10 (x + 1)

x = - \frac{3}{2}

Decimal Notation

x = - 1.5

Solution steps

4 x^{2} + 2 x - 1 = - 10 (x + 1)

Expand

- 10 (x + 1) : - 10 x - 10

4 x^{2} + 2 x - 1 = - 10 x - 10

Move

10

to the left side

4 x^{2} + 2 x + 9 = - 10 x

Move

10 x

to the left side

4 x^{2} + 12 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

1 2^{2} - 4 \cdot 4 \cdot 9 = 0

x_{1, 2} = \frac{- 12 \pm 0}{2 \cdot 4}

x = \frac{- 12}{2 \cdot 4}

\frac{- 12}{2 \cdot 4} = - \frac{3}{2}

x = - \frac{3}{2}

The solution to the quadratic equation is:

x = - \frac{3}{2}

4 x^{2} + 8 x = - 3

(x - 1) (\frac{3 - x}{2}) = 4

(x - 3) (x + 1) = 0

(x - 2)^{2} + 5 = 0

6 x^{2} + 20 x + 6 = 0

What are the solutions to the equation 4x^2+2x-1=-10(x+1) ?
The solutions to the equation 4x^2+2x-1=-10(x+1) are x=-3/2
Find the zeros of 4x^2+2x-1=-10(x+1)
The zeros of 4x^2+2x-1=-10(x+1) are x=-3/2