What are the solutions to the equation 6x^2+20x+6=0 ?

The solutions to the equation 6x^2+20x+6=0 are x=-1/3 ,x=-3

Find the zeros of 6x^2+20x+6=0

The zeros of 6x^2+20x+6=0 are x=-1/3 ,x=-3

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6 x^{2} + 20 x + 6 = 0

x = - \frac{1}{3}, x = - 3

Solution steps

6 x^{2} + 20 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 6 \cdot 6}{2 \cdot 6}

2 0^{2} - 4 \cdot 6 \cdot 6 = 16

x_{1, 2} = \frac{- 20 \pm 16}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 20 + 16}{2 \cdot 6}, x_{2} = \frac{- 20 - 16}{2 \cdot 6}

x = \frac{- 20 + 16}{2 \cdot 6} : - \frac{1}{3}

x = \frac{- 20 - 16}{2 \cdot 6} : - 3

The solutions to the quadratic equation are:

x = - \frac{1}{3}, x = - 3

2 r^{2} + r - 1 = 0

x^{2} + 4 a x = - 3 a^{2}

x^{2} - 5 x + 36 = 0

16 (5 x - 6)^{2} - 41 = - 37

(x - 3) (x - 1) = 15

What are the solutions to the equation 6x^2+20x+6=0 ?
The solutions to the equation 6x^2+20x+6=0 are x=-1/3 ,x=-3
Find the zeros of 6x^2+20x+6=0
The zeros of 6x^2+20x+6=0 are x=-1/3 ,x=-3