What are the solutions to the equation (x-1)((3-x)/2)=4 ?

The solutions to the equation (x-1)((3-x)/2)=4 are x=2-sqrt(7)i,x=2+sqrt(7)i

Find the zeros of (x-1)((3-x)/2)=4

The zeros of (x-1)((3-x)/2)=4 are x=2-sqrt(7)i,x=2+sqrt(7)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x - 1) (\frac{3 - x}{2}) = 4

x = 2 - 7 i, x = 2 + 7 i

Solution steps

(x - 1) (\frac{3 - x}{2}) = 4

Expand

(x - 1) (\frac{3 - x}{2}) : 2 x - \frac{x ^{2}}{2} - \frac{3}{2}

2 x - \frac{x ^{2}}{2} - \frac{3}{2} = 4

Move

4

to the left side

2 x + \frac{- x ^{2} - 3}{2} - 4 = 0

Write in the standard form

a x^{2} + b x + c = 0

- \frac{x ^{2}}{2} + 2 x - \frac{3}{2} - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - \frac{1}{2} ) ( - \frac{3}{2} - 4 )}{2 ( - \frac{1}{2} )}

Simplify

2^{2} - 4 (- \frac{1}{2}) (- \frac{3}{2} - 4) : 7 i

x_{1, 2} = \frac{- 2 \pm 7 i}{2 ( - \frac{1}{2} )}

Separate the solutions

x_{1} = \frac{- 2 + 7 i}{2 ( - \frac{1}{2} )}, x_{2} = \frac{- 2 - 7 i}{2 ( - \frac{1}{2} )}

x = \frac{- 2 + 7 i}{2 ( - \frac{1}{2} )} : 2 - 7 i

x = \frac{- 2 - 7 i}{2 ( - \frac{1}{2} )} : 2 + 7 i

The solutions to the quadratic equation are:

x = 2 - 7 i, x = 2 + 7 i

(x - 3) (x + 1) = 0

(x - 2)^{2} + 5 = 0

6 x^{2} + 20 x + 6 = 0

2 r^{2} + r - 1 = 0

x^{2} + 4 a x = - 3 a^{2}

What are the solutions to the equation (x-1)((3-x)/2)=4 ?
The solutions to the equation (x-1)((3-x)/2)=4 are x=2-sqrt(7)i,x=2+sqrt(7)i
Find the zeros of (x-1)((3-x)/2)=4
The zeros of (x-1)((3-x)/2)=4 are x=2-sqrt(7)i,x=2+sqrt(7)i