What are the solutions to the equation x^2+4ax=-3a^2 ?

The solutions to the equation x^2+4ax=-3a^2 are x=-a,x=-3a

Find the zeros of x^2+4ax=-3a^2

The zeros of x^2+4ax=-3a^2 are x=-a,x=-3a

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x^{2} + 4 a x = - 3 a^{2}

x = - a, x = - 3 a

Solution steps

x^{2} + 4 a x = - 3 a^{2}

Move

3 a^{2}

to the left side

x^{2} + 4 a x + 3 a^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 a \pm ( 4 a ) ^{2} - 4 \cdot 1 \cdot 3 a ^{2}}{2 \cdot 1}

Simplify

(4 a)^{2} - 4 \cdot 1 \cdot 3 a^{2} : 2 a

x_{1, 2} = \frac{- 4 a \pm 2 a}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 a + 2 a}{2 \cdot 1}, x_{2} = \frac{- 4 a - 2 a}{2 \cdot 1}

x = \frac{- 4 a + 2 a}{2 \cdot 1} : - a

x = \frac{- 4 a - 2 a}{2 \cdot 1} : - 3 a

The solutions to the quadratic equation are:

x = - a, x = - 3 a

x^{2} - 5 x + 36 = 0

16 (5 x - 6)^{2} - 41 = - 37

(x - 3) (x - 1) = 15

4 n^{2} - 9 n + 5 = 0

16 x^{2} = 12 x

What are the solutions to the equation x^2+4ax=-3a^2 ?
The solutions to the equation x^2+4ax=-3a^2 are x=-a,x=-3a
Find the zeros of x^2+4ax=-3a^2
The zeros of x^2+4ax=-3a^2 are x=-a,x=-3a