What are the solutions to the equation 16(5x-6)^2-41=-37 ?

The solutions to the equation 16(5x-6)^2-41=-37 are x= 13/10 ,x= 11/10

Find the zeros of 16(5x-6)^2-41=-37

The zeros of 16(5x-6)^2-41=-37 are x= 13/10 ,x= 11/10

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16 (5 x - 6)^{2} - 41 = - 37

x = \frac{13}{10}, x = \frac{11}{10}

Decimal Notation

x = 1.3, x = 1.1

Solution steps

16 (5 x - 6)^{2} - 41 = - 37

Move

41

to the right side

16 (5 x - 6)^{2} = 4

Divide both sides by

16

(5 x - 6)^{2} = \frac{1}{4}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 x - 6 = \frac{1}{4} : x = \frac{13}{10}

Solve

5 x - 6 = - \frac{1}{4} : x = \frac{11}{10}

The solutions to the quadratic equation are:

x = \frac{13}{10}, x = \frac{11}{10}

(x - 3) (x - 1) = 15

4 n^{2} - 9 n + 5 = 0

16 x^{2} = 12 x

x (5 x - 4) = 2

x^{2} + 4 x - 5 = 0

What are the solutions to the equation 16(5x-6)^2-41=-37 ?
The solutions to the equation 16(5x-6)^2-41=-37 are x= 13/10 ,x= 11/10
Find the zeros of 16(5x-6)^2-41=-37
The zeros of 16(5x-6)^2-41=-37 are x= 13/10 ,x= 11/10