What are the solutions to the equation s^2-2s-3=0 ?

The solutions to the equation s^2-2s-3=0 are s=3,s=-1

Find the zeros of s^2-2s-3=0

The zeros of s^2-2s-3=0 are s=3,s=-1

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s^{2} - 2 s - 3 = 0

s = 3, s = - 1

Solution steps

s^{2} - 2 s - 3 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 3) = 4

s_{1, 2} = \frac{- ( - 2 ) \pm 4}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- ( - 2 ) + 4}{2 \cdot 1}, s_{2} = \frac{- ( - 2 ) - 4}{2 \cdot 1}

s = \frac{- ( - 2 ) + 4}{2 \cdot 1} : 3

s = \frac{- ( - 2 ) - 4}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

s = 3, s = - 1

- x^{2} + 6 x - 5

x^{2} + 25 = - 10 x

- 2 x^{2} + 4 x - 6 = 0

x, x^{2} + y^{2} + z = 1

9 (5 x + 2)^{2} - 42 = 7

What are the solutions to the equation s^2-2s-3=0 ?
The solutions to the equation s^2-2s-3=0 are s=3,s=-1
Find the zeros of s^2-2s-3=0
The zeros of s^2-2s-3=0 are s=3,s=-1