What are the solutions to the equation 12x^2-252x+902=0 ?

The solutions to the equation 12x^2-252x+902=0 are x=(63+sqrt(1263))/6 ,x=(63-sqrt(1263))/6

Find the zeros of 12x^2-252x+902=0

The zeros of 12x^2-252x+902=0 are x=(63+sqrt(1263))/6 ,x=(63-sqrt(1263))/6

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12 x^{2} - 252 x + 902 = 0

x = \frac{63 + 1263}{6}, x = \frac{63 - 1263}{6}

Solution steps

12 x^{2} - 252 x + 902 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 252 ) \pm ( - 252 ) ^{2} - 4 \cdot 12 \cdot 902}{2 \cdot 12}

(- 252)^{2} - 4 \cdot 12 \cdot 902 = 41263

x_{1, 2} = \frac{- ( - 252 ) \pm 4 1263}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 252 ) + 4 1263}{2 \cdot 12}, x_{2} = \frac{- ( - 252 ) - 4 1263}{2 \cdot 12}

x = \frac{- ( - 252 ) + 4 1263}{2 \cdot 12} : \frac{63 + 1263}{6}

x = \frac{- ( - 252 ) - 4 1263}{2 \cdot 12} : \frac{63 - 1263}{6}

The solutions to the quadratic equation are:

x = \frac{63 + 1263}{6}, x = \frac{63 - 1263}{6}

7 m^{2} + 40 = 43 m

(x - 7)^{2} = 6

(x^{2} - 4 x + 4) = 0

2 x^{2} - 20 x = 0

6 x^{2} + 5 x - 21 = 0

What are the solutions to the equation 12x^2-252x+902=0 ?
The solutions to the equation 12x^2-252x+902=0 are x=(63+sqrt(1263))/6 ,x=(63-sqrt(1263))/6
Find the zeros of 12x^2-252x+902=0
The zeros of 12x^2-252x+902=0 are x=(63+sqrt(1263))/6 ,x=(63-sqrt(1263))/6