What are the solutions to the equation 0=x^2-4x-12 ?

The solutions to the equation 0=x^2-4x-12 are x=6,x=-2

Find the zeros of 0=x^2-4x-12

The zeros of 0=x^2-4x-12 are x=6,x=-2

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0 = x^{2} - 4 x - 12

x = 6, x = - 2

Solution steps

0 = x^{2} - 4 x - 12

Switch sides

x^{2} - 4 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 12) = 8

x_{1, 2} = \frac{- ( - 4 ) \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 8}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 8}{2 \cdot 1}

x = \frac{- ( - 4 ) + 8}{2 \cdot 1} : 6

x = \frac{- ( - 4 ) - 8}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 6, x = - 2

2 x^{2} - 10 x + 18 = 0

2 x^{2} - 8 b x = 2 b^{2}

- 9 x^{2} + 18 x = 0

4 r^{2} + 15 r + 7 = - 1

3 x^{2} + 2 (x^{2} - 20) = 16 - 2 x^{2}

What are the solutions to the equation 0=x^2-4x-12 ?
The solutions to the equation 0=x^2-4x-12 are x=6,x=-2
Find the zeros of 0=x^2-4x-12
The zeros of 0=x^2-4x-12 are x=6,x=-2