What are the solutions to the equation x^2-3x+20=0 ?

The solutions to the equation x^2-3x+20=0 are x= 3/2+i(sqrt(71))/2 ,x= 3/2-i(sqrt(71))/2

Find the zeros of x^2-3x+20=0

The zeros of x^2-3x+20=0 are x= 3/2+i(sqrt(71))/2 ,x= 3/2-i(sqrt(71))/2

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x^{2} - 3 x + 20 = 0

x = \frac{3}{2} + i \frac{71}{2}, x = \frac{3}{2} - i \frac{71}{2}

Solution steps

x^{2} - 3 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

Simplify

(- 3)^{2} - 4 \cdot 1 \cdot 20 : 71 i

x_{1, 2} = \frac{- ( - 3 ) \pm 71 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 71 i}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 71 i}{2 \cdot 1}

x = \frac{- ( - 3 ) + 71 i}{2 \cdot 1} : \frac{3}{2} + i \frac{71}{2}

x = \frac{- ( - 3 ) - 71 i}{2 \cdot 1} : \frac{3}{2} - i \frac{71}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2} + i \frac{71}{2}, x = \frac{3}{2} - i \frac{71}{2}

x, x^{2} + y^{2} + z^{2} = 0

4 x^{2} - 16 x - 3

- 0.2 x^{2} + 8 x + 20 = - 2.4 x + 97.4

6 x - x^{2} = 2 x

4 x^{2} - 24 x + 13

What are the solutions to the equation x^2-3x+20=0 ?
The solutions to the equation x^2-3x+20=0 are x= 3/2+i(sqrt(71))/2 ,x= 3/2-i(sqrt(71))/2
Find the zeros of x^2-3x+20=0
The zeros of x^2-3x+20=0 are x= 3/2+i(sqrt(71))/2 ,x= 3/2-i(sqrt(71))/2