What are the solutions to the equation solvefor x,x^2+y^2+z^2=0 ?

The solutions to the equation solvefor x,x^2+y^2+z^2=0 are x=sqrt(-y^2-z^2),x=-sqrt(-y^2-z^2)

Find the zeros of solvefor x,x^2+y^2+z^2=0

The zeros of solvefor x,x^2+y^2+z^2=0 are x=sqrt(-y^2-z^2),x=-sqrt(-y^2-z^2)

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solve for

x, x^{2} + y^{2} + z^{2} = 0

x = - y^{2} - z^{2}, x = - - y^{2} - z^{2}

Solution steps

x^{2} + y^{2} + z^{2} = 0

Move

y^{2}

to the right side

x^{2} + z^{2} = - y^{2}

Move

z^{2}

to the right side

x^{2} = - y^{2} - z^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - y^{2} - z^{2}, x = - - y^{2} - z^{2}

4 x^{2} - 16 x - 3

- 0.2 x^{2} + 8 x + 20 = - 2.4 x + 97.4

6 x - x^{2} = 2 x

4 x^{2} - 24 x + 13

x^{2} - 3 x + 11 = 9

What are the solutions to the equation solvefor x,x^2+y^2+z^2=0 ?
The solutions to the equation solvefor x,x^2+y^2+z^2=0 are x=sqrt(-y^2-z^2),x=-sqrt(-y^2-z^2)
Find the zeros of solvefor x,x^2+y^2+z^2=0
The zeros of solvefor x,x^2+y^2+z^2=0 are x=sqrt(-y^2-z^2),x=-sqrt(-y^2-z^2)