What are the solutions to the equation -0.2x^2+8x+20=-2.4x+97.4 ?

The solutions to the equation -0.2x^2+8x+20=-2.4x+97.4 are x=9,x=43

Find the zeros of -0.2x^2+8x+20=-2.4x+97.4

The zeros of -0.2x^2+8x+20=-2.4x+97.4 are x=9,x=43

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- 0.2 x^{2} + 8 x + 20 = - 2.4 x + 97.4

x = 9, x = 43

Solution steps

- 0.2 x^{2} + 8 x + 20 = - 2.4 x + 97.4

Multiply both sides by

10

- 2 x^{2} + 80 x + 200 = - 24 x + 974

Move

974

to the left side

- 2 x^{2} + 80 x - 774 = - 24 x

Move

24 x

to the left side

- 2 x^{2} + 104 x - 774 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 104 \pm 10 4 ^{2} - 4 ( - 2 ) ( - 774 )}{2 ( - 2 )}

10 4^{2} - 4 (- 2) (- 774) = 68

x_{1, 2} = \frac{- 104 \pm 68}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 104 + 68}{2 ( - 2 )}, x_{2} = \frac{- 104 - 68}{2 ( - 2 )}

x = \frac{- 104 + 68}{2 ( - 2 )} : 9

x = \frac{- 104 - 68}{2 ( - 2 )} : 43

The solutions to the quadratic equation are:

x = 9, x = 43

6 x - x^{2} = 2 x

4 x^{2} - 24 x + 13

x^{2} - 3 x + 11 = 9

x, x^{2} - y^{2} + 4 x + 6 y - 5 = 0

x, 5 x^{2} + 5 y^{2} - 10 x - 10 y = - 25

What are the solutions to the equation -0.2x^2+8x+20=-2.4x+97.4 ?
The solutions to the equation -0.2x^2+8x+20=-2.4x+97.4 are x=9,x=43
Find the zeros of -0.2x^2+8x+20=-2.4x+97.4
The zeros of -0.2x^2+8x+20=-2.4x+97.4 are x=9,x=43