What are the solutions to the equation 2x^2=8x+64 ?

The solutions to the equation 2x^2=8x+64 are x=8,x=-4

Find the zeros of 2x^2=8x+64

The zeros of 2x^2=8x+64 are x=8,x=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} = 8 x + 64

x = 8, x = - 4

Solution steps

2 x^{2} = 8 x + 64

Move

64

to the left side

2 x^{2} - 64 = 8 x

Move

8 x

to the left side

2 x^{2} - 64 - 8 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - 8 x - 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 2 ( - 64 )}{2 \cdot 2}

(- 8)^{2} - 4 \cdot 2 (- 64) = 24

x_{1, 2} = \frac{- ( - 8 ) \pm 24}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 24}{2 \cdot 2}, x_{2} = \frac{- ( - 8 ) - 24}{2 \cdot 2}

x = \frac{- ( - 8 ) + 24}{2 \cdot 2} : 8

x = \frac{- ( - 8 ) - 24}{2 \cdot 2} : - 4

The solutions to the quadratic equation are:

x = 8, x = - 4

x^{2} + 4 x - 36 = 0

2 x^{2} - 4 x + 3

(x + 2)^{2} + 3 (x + 1) (x + 4) = (x - 3) (x + 3) - 1

8 x^{2} - 22 x + 15 = 0

2 x - x^{2} = x^{2}

What are the solutions to the equation 2x^2=8x+64 ?
The solutions to the equation 2x^2=8x+64 are x=8,x=-4
Find the zeros of 2x^2=8x+64
The zeros of 2x^2=8x+64 are x=8,x=-4