What are the solutions to the equation x^2+4x-36=0 ?

The solutions to the equation x^2+4x-36=0 are x=2(sqrt(10)-1),x=-2(1+sqrt(10))

Find the zeros of x^2+4x-36=0

The zeros of x^2+4x-36=0 are x=2(sqrt(10)-1),x=-2(1+sqrt(10))

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x^{2} + 4 x - 36 = 0

x = 2 (10 - 1), x = - 2 (1 + 10)

Solution steps

x^{2} + 4 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 36 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 36) = 410

x_{1, 2} = \frac{- 4 \pm 4 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 4 10}{2 \cdot 1}, x_{2} = \frac{- 4 - 4 10}{2 \cdot 1}

x = \frac{- 4 + 4 10}{2 \cdot 1} : 2 (10 - 1)

x = \frac{- 4 - 4 10}{2 \cdot 1} : - 2 (1 + 10)

The solutions to the quadratic equation are:

x = 2 (10 - 1), x = - 2 (1 + 10)

2 x^{2} - 4 x + 3

(x + 2)^{2} + 3 (x + 1) (x + 4) = (x - 3) (x + 3) - 1

8 x^{2} - 22 x + 15 = 0

2 x - x^{2} = x^{2}

3 (5 x + 7)^{2} - 18 = 48

What are the solutions to the equation x^2+4x-36=0 ?
The solutions to the equation x^2+4x-36=0 are x=2(sqrt(10)-1),x=-2(1+sqrt(10))
Find the zeros of x^2+4x-36=0
The zeros of x^2+4x-36=0 are x=2(sqrt(10)-1),x=-2(1+sqrt(10))