What are the solutions to the equation -3x^2-39x+133=9x+1 ?

The solutions to the equation -3x^2-39x+133=9x+1 are x=-2(4+3sqrt(3)),x=2(3sqrt(3)-4)

Find the zeros of -3x^2-39x+133=9x+1

The zeros of -3x^2-39x+133=9x+1 are x=-2(4+3sqrt(3)),x=2(3sqrt(3)-4)

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- 3 x^{2} - 39 x + 133 = 9 x + 1

x = - 2 (4 + 33), x = 2 (33 - 4)

Solution steps

- 3 x^{2} - 39 x + 133 = 9 x + 1

Move

1

to the left side

- 3 x^{2} - 39 x + 132 = 9 x

Move

9 x

to the left side

- 3 x^{2} - 48 x + 132 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 48 ) \pm ( - 48 ) ^{2} - 4 ( - 3 ) \cdot 132}{2 ( - 3 )}

(- 48)^{2} - 4 (- 3) \cdot 132 = 363

x_{1, 2} = \frac{- ( - 48 ) \pm 36 3}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 48 ) + 36 3}{2 ( - 3 )}, x_{2} = \frac{- ( - 48 ) - 36 3}{2 ( - 3 )}

x = \frac{- ( - 48 ) + 36 3}{2 ( - 3 )} : - 2 (4 + 33)

x = \frac{- ( - 48 ) - 36 3}{2 ( - 3 )} : 2 (33 - 4)

The solutions to the quadratic equation are:

x = - 2 (4 + 33), x = 2 (33 - 4)

12 x^{2} - 184 x + 480 = 0

(5 x + 8)^{2} = 49

x^{2} - 6 x + 5 = 0

4 x^{2} + 24 x - 11 = 0

25 x^{2} - 50 x + 26 = 0

What are the solutions to the equation -3x^2-39x+133=9x+1 ?
The solutions to the equation -3x^2-39x+133=9x+1 are x=-2(4+3sqrt(3)),x=2(3sqrt(3)-4)
Find the zeros of -3x^2-39x+133=9x+1
The zeros of -3x^2-39x+133=9x+1 are x=-2(4+3sqrt(3)),x=2(3sqrt(3)-4)