What are the solutions to the equation r^2-r-1=0 ?

The solutions to the equation r^2-r-1=0 are r=(1+sqrt(5))/2 ,r=(1-sqrt(5))/2

Find the zeros of r^2-r-1=0

The zeros of r^2-r-1=0 are r=(1+sqrt(5))/2 ,r=(1-sqrt(5))/2

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r^{2} - r - 1 = 0

r = \frac{1 + 5}{2}, r = \frac{1 - 5}{2}

Solution steps

r^{2} - r - 1 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 1) = 5

r_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- ( - 1 ) + 5}{2 \cdot 1}, r_{2} = \frac{- ( - 1 ) - 5}{2 \cdot 1}

r = \frac{- ( - 1 ) + 5}{2 \cdot 1} : \frac{1 + 5}{2}

r = \frac{- ( - 1 ) - 5}{2 \cdot 1} : \frac{1 - 5}{2}

The solutions to the quadratic equation are:

r = \frac{1 + 5}{2}, r = \frac{1 - 5}{2}

x^{2} - x = 9

3 x^{2} + x + 7 = x^{2} + 10

4 x^{2} = - 1

7 - 7 x = (3 x + 2) (x - 1)

y, M = (y - 3)^{2} + 4 y

What are the solutions to the equation r^2-r-1=0 ?
The solutions to the equation r^2-r-1=0 are r=(1+sqrt(5))/2 ,r=(1-sqrt(5))/2
Find the zeros of r^2-r-1=0
The zeros of r^2-r-1=0 are r=(1+sqrt(5))/2 ,r=(1-sqrt(5))/2