What are the solutions to the equation -2x^2+28x-148=0 ?

The solutions to the equation -2x^2+28x-148=0 are x=7-5i,x=7+5i

Find the zeros of -2x^2+28x-148=0

The zeros of -2x^2+28x-148=0 are x=7-5i,x=7+5i

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- 2 x^{2} + 28 x - 148 = 0

x = 7 - 5 i, x = 7 + 5 i

Solution steps

- 2 x^{2} + 28 x - 148 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 28 \pm 2 8 ^{2} - 4 ( - 2 ) ( - 148 )}{2 ( - 2 )}

Simplify

2 8^{2} - 4 (- 2) (- 148) : 20 i

x_{1, 2} = \frac{- 28 \pm 20 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 28 + 20 i}{2 ( - 2 )}, x_{2} = \frac{- 28 - 20 i}{2 ( - 2 )}

x = \frac{- 28 + 20 i}{2 ( - 2 )} : 7 - 5 i

x = \frac{- 28 - 20 i}{2 ( - 2 )} : 7 + 5 i

The solutions to the quadratic equation are:

x = 7 - 5 i, x = 7 + 5 i

- 4 x^{2} + 12 x = 0

3 x^{2} - 8 x - 2 = 0

(x - 4) (x + 6) = 0

3 n^{2} = 27

x^{2} + 22 x = 0

What are the solutions to the equation -2x^2+28x-148=0 ?
The solutions to the equation -2x^2+28x-148=0 are x=7-5i,x=7+5i
Find the zeros of -2x^2+28x-148=0
The zeros of -2x^2+28x-148=0 are x=7-5i,x=7+5i