What are the solutions to the equation s^2-s+10=0 ?

The solutions to the equation s^2-s+10=0 are s= 1/2+i(sqrt(39))/2 ,s= 1/2-i(sqrt(39))/2

Find the zeros of s^2-s+10=0

The zeros of s^2-s+10=0 are s= 1/2+i(sqrt(39))/2 ,s= 1/2-i(sqrt(39))/2

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s^{2} - s + 10 = 0

s = \frac{1}{2} + i \frac{39}{2}, s = \frac{1}{2} - i \frac{39}{2}

Solution steps

s^{2} - s + 10 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

Simplify

(- 1)^{2} - 4 \cdot 1 \cdot 10 : 39 i

s_{1, 2} = \frac{- ( - 1 ) \pm 39 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- ( - 1 ) + 39 i}{2 \cdot 1}, s_{2} = \frac{- ( - 1 ) - 39 i}{2 \cdot 1}

s = \frac{- ( - 1 ) + 39 i}{2 \cdot 1} : \frac{1}{2} + i \frac{39}{2}

s = \frac{- ( - 1 ) - 39 i}{2 \cdot 1} : \frac{1}{2} - i \frac{39}{2}

The solutions to the quadratic equation are:

s = \frac{1}{2} + i \frac{39}{2}, s = \frac{1}{2} - i \frac{39}{2}

- 2 x^{2} + 28 x - 148 = 0

- 4 x^{2} + 12 x = 0

3 x^{2} - 8 x - 2 = 0

(x - 4) (x + 6) = 0

3 n^{2} = 27

What are the solutions to the equation s^2-s+10=0 ?
The solutions to the equation s^2-s+10=0 are s= 1/2+i(sqrt(39))/2 ,s= 1/2-i(sqrt(39))/2
Find the zeros of s^2-s+10=0
The zeros of s^2-s+10=0 are s= 1/2+i(sqrt(39))/2 ,s= 1/2-i(sqrt(39))/2