What are the solutions to the equation 3n^2=27 ?

The solutions to the equation 3n^2=27 are n=3,n=-3

Find the zeros of 3n^2=27

The zeros of 3n^2=27 are n=3,n=-3

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3 n^{2} = 27

n = 3, n = - 3

Solution steps

3 n^{2} = 27

Divide both sides by

3

n^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

n = 9, n = - 9

9 = 3

- 9 = - 3

n = 3, n = - 3

x^{2} + 22 x = 0

x^{2} + 6 x + 9 = 81

6 x^{2} - 3 x - 3 = 0

3 x^{2} - 2 x - 20 = 0

(x + 8)^{2} = 81

What are the solutions to the equation 3n^2=27 ?
The solutions to the equation 3n^2=27 are n=3,n=-3
Find the zeros of 3n^2=27
The zeros of 3n^2=27 are n=3,n=-3